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Studentka2010 [4]
3 years ago
11

Read the scientific question below.

Chemistry
1 answer:
svetlana [45]3 years ago
8 0
If we fertilize a plant, then its height increases fast. Always use if then format
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If u answer will answer the brainlest
klio [65]

Answer:

the electricity dissipated, because of the time.

Explanation:

electricity dissipates.

6 0
2 years ago
A gas mixture contains 1.61 moles of hydrogen and 2.31 moles of oxygen. What is the mole fraction of oxygen?
agasfer [191]

Answer: option B. 0.59

Explanation:Please see attachment for explanation

5 0
3 years ago
If a volume of gas 177.6mL was collected at a temperature of 25.8C and the pressure is 799.7 torr, what is the original concentr
Step2247 [10]

Answer:

The original concentration of the acid was 0.605 M

Explanation:

Step 1: Data given

Volume of gas = 177.6 mL = 0.1176 L

Temperature = 25.8 °C = 298.95 K

Pressure = 799.7 torr = 799.7/ 760 = 1.0522368 atm

Volume of acid needed to react = 12.6 mL = 0.0126 L

Step 2: Calculate moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with n = the number of moles = TO BE DETERMINED

⇒with p = the pressure of the gas = 799.7 torr = 1.0522368 atm

⇒with V = the volume of the gas = 177.6 mL = 0.1776 L

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 25.8 °C = 298.95 K

n = 0.007618 moles

Step 3: Calculate original concentration

We need 0.007618 moles of acid to react with the same amount of moles gas

Concentration acid = moles / volume

Concentration acid = 0.007618 moles / 0.0126 L

Concentration acid = 0.605 M

The original concentration of the acid was 0.605 M

5 0
3 years ago
Define the term macromolecule
makkiz [27]

Explanation:

a molecule containing a very large number of atoms, such as a protein, nucleic acid, or synthetic polymer.

4 0
3 years ago
Una muestra de oxígeno ocupa 4.2 litros a 760 mm de hg . ¿ cual será el volumen del oxigeno a 415 mm de hg , si la temperatura p
ddd [48]

Teniendo en cuenta la ley de Boyle, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Al aumentar el volumen, las partículas (átomos o moléculas) del gas tardan más en llegar a las paredes del recipiente y por lo tanto chocan menos veces por unidad de tiempo contra ellas. Esto significa que la presión será menor porque ésta representa la frecuencia de choques del gas contra las paredes.

De esta manera se relaciona la presión y el volumen, determinando la ley de Boyle que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:

P×V=k

Teniendo un estado inicial 1 y final 2, se cumple:

P₁×V₁= P₂×V₂

En este caso, se sabe que:

  • P₁= 760 mmHg
  • V₁= 4.2 L
  • P₂= 415 mmHg
  • V₂= ?

Reemplazando en la expresión matemática para la Ley de Boyle:

760 mmHg× 4.2 L= 415 mmHg× V₂

Resolviendo:

(760 mmHg× 4.2 L)÷ 415 mmHg= V₂

<u><em>7,69 L= V₂</em></u>

Finalmente, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Aprende más:

  • <u>brainly.com/question/23993136?referrer=searchResults</u>
  • <u>brainly.com/question/19128249?referrer=searchResults</u>
  • <u>brainly.com/question/20719227?referrer=searchResults</u>

5 0
2 years ago
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