Hey there!
Al + HCl → H₂ + AlCl₃
Balance Cl.
1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.
Al + 3HCl → H₂ + AlCl₃
Balance H.
3 on the left, 2 on the right. We have to start by multiplying everything else by 2.
2Al + 3HCl → 2H₂ + 2AlCl₃
Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.
2Al + 4HCl → 2H₂ + 2AlCl₃
Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.
2Al + 6HCl → 2H₂ + 2AlCl₃
Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.
2Al + 6HCl → 3H₂ + 2AlCl₃
Balance Al.
2 on the left, 2 on the right. Already balanced.
Here is our final balanced equation:
2Al + 6HCl → 3H₂ + 2AlCl₃
Hope this helps!
A kilogram is a measure of mass; 1,000 grams
Answer:
energy
Explanation:
The photon of light that is emitted as an electron drops back to its original orbit is energy and this energy is released during de-excitation process.
The electron is jumped into higher level and back into lower level by absorbing and releasing the energy.
The process is called excitation and de-excitation.
Excitation:
When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits. For example if electron jumped from K to L it must absorbed the energy which is equal the energy difference of these two level. The excited electron thus move back to lower energy level which is K by releasing the energy because electron can not stay longer in higher energy level and comes to ground state.
De-excitation:
When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum
Answer:
0.725 mol
Explanation:
Moles are calculated as the given mass divided by the molecular mass.
i.e. ,
moles = ( mass / molecular mass )
since,
mass of KNO₃ = 58.6 g ( given )
Molecular mass of KNO₃ = 101 g / mol
Therefore,
moles of KNO₃ = 58.6 g / 101 g / mol
moles of KNO₃ = 0.58 mol
From the balanced reaction ,
4 KNO₃ (s) ---> 2K₂O (s) + 2N₂ (g) + 5O₂ (g)
By the decomposition of 4 mol of KNO₃ , 5 mol of O₂ are formed ,
hence, unitary method is used as,
1 mol of KNO₃ gives 5 / 4 mol O₂
Therefore,
0.58 mol of KNO₃ , gives , 5 / 4 * 0.58 mol of O₂
Solving,
0.58 mol of KNO₃ , gives , 0.725 mol of O₂
Therefore,
58.6g of KNO₃ gives 0.725 mol of O₂.
As we know that
P.E. = mgh
where,
P.E. = Potential energy of the object =?
m= mass of object= 3kg
g= acceleration due to gravity = 9.8 ms^-2
h = height between object and animal = 0 m
Then
P.E. = 3× 9.8 × 0 = 0 Joules or 0J
<em>Have a luvely day!</em>
