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AysviL [449]
3 years ago
11

There are molecules of carbon dioxide (CO2) in 102.5 grams.

Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

1.403x10²⁴ molecules

Explanation:

In order to calculate how many molecules of CO₂ are there in 102.5 g of the compound, we first<u> convert grams to moles</u> using its <em>molar mass</em>:

  • 102.5 g ÷ 44 g/mol = 2.330 mol CO₂

Now we <u>convert moles into molecules </u>using <em>Avogadro's number</em>:

  • 2.330 mol * 6.023x10²³ molecules/mol = 1.403x10²⁴ molecules
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Follows are the solution to this question:

Explanation:

Please find the complete solution in the attached file.

7 0
3 years ago
Atoms of iron (fe) and sulfur (s) form iron sulfide (fes) when the iron atom donates electrons to the sulfur atom. the type of b
marysya [2.9K]

Answer:

               The type of bond formed in FeS would be <u>Polar Covalent Bond</u>.

Explanation:

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

               Less than 0.4 then it is Non Polar Covalent  Bond

               Between 0.4 and 1.7 then it is Polar Covalent  Bond

               Greater than 1.7 then it is Ionic  Bond

For Fe and S,

                   E.N of Sulfur           =   2.58

                   E.N of Iron              =   1.83

                                                  ________

                   E.N Difference            0.75          (Polar Covalent Bond)


4 0
3 years ago
The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
                                           = 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³
8 0
3 years ago
A sucrose packet contains 4.0g sucrose C12H22O11, how many moles of sucrose does the packet contain?
SpyIntel [72]

Answer:

And we have to calculate the number of moles of sucrose present in a lb mass of sucrose: Moles of sucrose=454⋅g342.30⋅g⋅mol−1=1.33⋅mol .

Explanation:

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8 0
3 years ago
3.2 moles of H3PO4 to grams
Nimfa-mama [501]

Answer:

313, 6grams of H3PO4

Explanation:

We calculate the weight of 1 mol of H3PO4:

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3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4

4 0
3 years ago
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