To solve this multiply through by the LCM of 4 and 6, which is 12:-
12 * x/4 - 12 * x/6 = 1*12
3x - 2x = 12
x = 12 answer
So the dependent is the number of games because it's not definite they dont know for sure. so the domain always involves money!!! always! the range wiyld be the numbers they migh play like 8-10 so 4 to 8 is the range value. so determining off of that the indepedent variable would be the total cost becuase it wont change so your answer is C hope this helped have a good day!!!
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
<h3>
HJ = 15</h3>
Step-by-step explanation:
To get the length of segment HJ if H lies at (-1,7) and J lies at (8,-5), we will use the formula for calculating the distance between two points as shown;
D = √(x₂-x₁)²+(y₂-y₁)²
From the coordinates x₁ = -1, y₁ = 7, x₂ = 8, y₂ = -5
HJ = √(8-(-1))²+(-5-7)²
HJ = √(8+1)²+(-12)²
HJ = √81+144
HJ = √225
HJ = 15
<em>Hence the length of segment HJ is 15 units</em>
Brand A costs $2 per ounce, B is $1, C is $0.50(?) I think
