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Olegator [25]
2 years ago
6

Please do 3 hurry!!!!

Mathematics
1 answer:
Sedaia [141]2 years ago
4 0

Here is the answer above. Click to view

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5) How many thousands are there in 2 158 621?​
never [62]

Answer:

2,158,621 = 2 (i think)

6 0
3 years ago
Read 2 more answers
Select the statement that is FALSE. The range is never greater than the greatest value of a data set. The interquartile range is
Nata [24]

Answer:

The interquartile range is the difference between the highest and lowest values in the middle of a data set.

Step-by-step explanation:

The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.

The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.

The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.

6 0
3 years ago
This the questions that have me stuck​
IRINA_888 [86]
First a and then b.
4 0
3 years ago
B\7+12=-8 helpppppppp
vodka [1.7K]

Answer:

b = -152

Step-by-step explanation:

  1. 7 + 12 = 19
  2. Plug 19 in: \frac{b}{19} = -8  
  3. Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

I hope this helps!

8 0
2 years ago
Describe how to find the least common multiple of three numbers
notka56 [123]
Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only. 
Notice that 6 and 8 have a common factor 2, so pick up the 2;
 6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15

this is basically how it is done. I believe you can explain better in your own words. 

3 0
3 years ago
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