The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
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21,500 this is the answer
First, start off with the x-axis. -6.5, 1 becomes 6.5, 1. This is because point T is 6.5 to the left of the x-axis line, so our new point would be 6.5 to the right of the x-axis line. Same thing for the y-axis, (6.5, 1) would become (6.5, -1).
Answer:
A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.
B) 3.39% per year
C) $182,000
Step-by-step explanation:
A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.
165000 = 100000(1 +r)^15
1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root
1.03394855265 -1 = r ≈ 0.0339
The value was multiplied by about 1.0339 each year.
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B) The value increased by about 3.39% per year.
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C) S = $100,000(1.03394855265)^18 ≈ $182,000
D. Nine hundred fifty-for thousandths
