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Hunter-Best [27]
3 years ago
8

A spider walks on the outside of a box from point A to B to C to D

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

The path consists of 4 line segments. Each line segment is the hypotenuse of a different right triangle.

length of line segment AB = \sqrt{2^{2}+5^{2}  } =\sqrt{29} =5.39cm

length of line segment BC = \sqrt{3^{2}+4^{2}  } =\sqrt{25} =5cm

length of line segment CD = \sqrt{3^{2}+5^{2}  } =\sqrt{34} =5.83cm

length of line segment DE =\sqrt{2.5^{2}+3^{2} } } =\sqrt{15.25} =3.91cm

The total length of the spider's path is about 20.13 cm.

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Both ratios simplified equal 1:6.
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hope this helps

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