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Hunter-Best [27]
2 years ago
8

A spider walks on the outside of a box from point A to B to C to D

Mathematics
1 answer:
Nikitich [7]2 years ago
6 0

The path consists of 4 line segments. Each line segment is the hypotenuse of a different right triangle.

length of line segment AB = \sqrt{2^{2}+5^{2}  } =\sqrt{29} =5.39cm

length of line segment BC = \sqrt{3^{2}+4^{2}  } =\sqrt{25} =5cm

length of line segment CD = \sqrt{3^{2}+5^{2}  } =\sqrt{34} =5.83cm

length of line segment DE =\sqrt{2.5^{2}+3^{2} } } =\sqrt{15.25} =3.91cm

The total length of the spider's path is about 20.13 cm.

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the cost y (in dollars) for x pounds of deli meat is represented by the equation y=3.5x, graph the equation
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Answer:

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8 0
2 years ago
Thanks for your answer​
inna [77]

I hope this helps you feel free to contact me

4 0
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8 0
3 years ago
Solve the problem using the six-step method: A pharmacist found at the end of the day she had 7/4 as many prescriptions for anti
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<h3>Given</h3>

1 (female) pharmacist counting prescriptions at the end of the day

(prescriptions for antibiotics) = (7/4)×(prescriptions for tranquilizers)

33 = (prescriptions for tranquilizers) + (prescriptions for antibiotics)

<h3>Find</h3>

The number of (prescriptions for tranquilizers)

<h3>Solution</h3>

Let <em>x</em> represent the number of <em>prescriptions for tranquilizers</em>. Then the number of prescriptions for antibiotics is (7/4)x, and the total number of prescriptions is

... 33 = x + (7/4)x . . . . . . . . . . put the given information in the given relation

... 33 = (4/4)x + (7/4)x . . . . . . rewrite 1 as 4/4 so we can add to 7/4

... 33 = ((4+7)/4)x = (11/4)x . . . simplify

... 33×(4/11) = (4/11)×(11/4)x . . . multiply by the reciprocal of the coefficient of x

... 12 = x . . . . . . . . . . . . . . . . . simplify

The pharmacist had 12 prescriptions for tranquilizers.

The pharmacist had 33-12 = 21 prescriptions for antibiotics.

There was 1 pharmacist and 33 prescriptions.

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Determine the slope and the y-intercept <br><br> 4x+5y=8<br> Answer:
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