Solve for c :
x⁴ + cx² + 100 = 0
cx² = -(x⁴ + 100)
c = - (x⁴ + 100)/x²
If x = 0, the right side is undefined and c would have no solution.
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
G is not TRUE.
Step-by-step explanation:
using the law A+B = B+A
PYTHAGOREAN THEOREM
A²+B² =C² is equal to B² +A² = C²
So for A²,
B² - c² = A. remember if a positive number move from the left to the right over an equal sign it becomes negative and vice versa
B²
C² - A²= B²
Answer:
5 4/5
Step-by-step explanation:
First of all subtract the whole number, 2, from 8 1/5
You would get 6 1/5
Now subtract 2/5 from that, or set up an equation like:
6 + 1/5 - 2/5
you would get 6 - 1/5 or 5 4/5
-Chetan K