Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
A) For f(-1) we use the part of the piecewise function for when x < 0 because -1 < 0. Plug in -1 for x:
2(-1) + 3 = 1
b) For f(0), we use the part for when x

0.
4(0) + 5 = 5
c) For f(2) we use the part for when x

0.
4(2) + 5 = 13
C(s) = 175s + 4500 or y = 175x + 4500
cost of 12 tons of sugar...
C(12) = 175(12) + 4500
C(12) = 2100 + 4500
C(12) = 6600....so 12 tons of sugar will cost u $ 6600
To obtain x, we can sum the angles < AQB and < BQC
=> 5X + 8X - 24
=> 13X -24
we are also told that that the sum of their angles is 80
13X - 24 = 80
13 X = 24 + 80
13X = 104
Divide both sides by 13
x = 104/13
x = 8
Answer:
-163.64..................