Splitting up [0, 3] into
equally-spaced subintervals of length
gives the partition
![\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%20%5Cdfrac3n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac3n%2C%20%5Cdfrac6n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac6n%2C%20%5Cdfrac9n%5Cright%5D%20%5Ccup%20%5Ccdots%20%5Ccup%20%5Cleft%5B%5Cdfrac%7B3%28n-1%29%7Dn%2C%203%5Cright%5D)
where the right endpoint of the
-th subinterval is given by the sequence

for
.
Then the definite integral is given by the infinite Riemann sum

Answer is 11/25 games lost which is 44%.
Step by step. 25 games minus 14 they won equals 11 games lost out of 25.
11 out of 25 = 11/25.
11/25 as a % - 11 divided by 25 = .44 which is 44%.
Check your work, 44% of 25 games = 11 games lost.
Problem solved.
Answer:
Step-by-step explanation:
I'm guessing A and J. Makes the most sense.
Answer:
a, (5;1) R = 
b, (-2; 4) R = 
c, (4;7) R = 7
d, (-3; -6) R = 7
Step-by-step explanation: