Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
D=100(opposites angles are equal)
A=C=80 (adj angles are supplementry)
Step-by-step explanation:
Answer:
(x − 2) = 3
Remove the bracket
x - 2 = 3
Group the constants at one side of the equation
x = 2 + 3
x = 5
Therefore x = 5.00 to 3 significant figures.
Hope this helps
50
thats it
ENV MEASURE IS 50!!!!!!!!!!!!!!
