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xxMikexx [17]
3 years ago
9

Please help and explain i will give brainly if you do that

Mathematics
2 answers:
Furkat [3]3 years ago
7 0
The slope is:8
Because
M=rise/run
Or
Y2-Y1/X2-X1
Sooo…
-8-0/-3-(-2)
Or 8

Hope this helps:)
Mkey [24]3 years ago
3 0
The slope would be 8.

Explanation:
Pick any 2 points. For example (0,16) and (1,24)
Use the formula which is *m=y2-y1/x2-x1*
Sub in y2 with 24 and y1 with 16. Then sub in x2 with 1 and x1 with 0.
Subtract and you should get 8/1 which simplifies to just 8 and that is your slope since you were solving for m=slope.

Hope this helps and you understand!
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an amusement park sold 46 child tickets. The other 4 tickets it sold were adult tickets. What is the ratio of the number of adul
Alja [10]

Answer:

2:46

1:23

Step-by-step explanation:

5 0
3 years ago
How long will it take for an investment to triple if it is compounded continuously at 12%
myrzilka [38]

Answer:

9.694 years

Step-by-step explanation:

Let the investment is $P.

So, we are asked to determine the time it will grow to triple with the compound interest rate of 12%.

Let the time is y years.

So, from the formula of compound interest we can write

3P = P(1 + \frac{12}{100} )^{y}

⇒ (1 + \frac{12}{100} )^{y} = 3

⇒ (1.12)^{y} = 3

Now, taking log both sides we get,

y log 1.12 = log 3 {Since, \log a^{b} = b \log a }

⇒ 0.04922y = 0.477712

⇒ y = 9.694 years (Answer)

3 0
3 years ago
Joanna needs a book to prop up a table leg. She randomly selects a book , and selects another book . What is probability that sh
Stolb23 [73]
Id say 40%
because 8 are math so 9 of them are other 
3 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
Whats the commisson of 660 in 10%
Sholpan [36]

Answer:

0,10×660=66

660-66= 594

6 0
3 years ago
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