The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
I'm not a 100% sure but I feel strong about is
The component in the mixture with the lowest density would be the component floating on the top of the mixture, i.e. the lightest in weight. Therefore, it would be the sawdust.
<h3><u>Answer;</u></h3>
Two glucose molecules
<h3><u>Explanation;</u></h3>
- Maltose is a disaccharide that is made up of two glucose molecules joined with an alpha(1-4) bond.
- <em><u>Maltose is produced by the enzymatic hydrolysis of starch, a polysaccharide, catalyzed by the enzyme amylase. Maltose is then hydrolyzed by the enzyme maltase to produce two molecules of d-glucose.</u></em>
- <em><u>The enzyme maltase efficiently catalyses the hydrolysis of maltose into 2 glucose molecules. </u></em>
The average atomic mass in amu of element X is 58.42 amu
The average atomic mass is the sum of the mass number of each of the isotopes multiplied by their respective abundances.
So;
The average atomic mass of element X is;
(58 * 0.68) + (60 * 0.26) + (0.06 * 62)
= 39.44 + 15.26 + 3.72
= 58.42 amu
The average atomic mass in amu of X is 58.42 amu.
Learn more: brainly.com/question/13292428
Answer:
1.135 M.
Explanation:
- For the reaction: <em>2HI → H₂ + I₂,</em>
The reaction is a second order reaction of HI,so the rate law of the reaction is: Rate = k[HI]².
- To solve this problem, we can use the integral law of second-order reactions:
<em>1/[A] = kt + 1/[A₀],</em>
where, k is the reate constant of the reaction (k = 1.57 x 10⁻⁵ M⁻¹s⁻¹),
t is the time of the reaction (t = 8 hours x 60 x 60 = 28800 s),
[A₀] is the initial concentration of HI ([A₀] = ?? M).
[A] is the remaining concentration of HI after hours ([A₀] = 0.75 M).
∵ 1/[A] = kt + 1/[A₀],
∴ 1/[A₀] = 1/[A] - kt
∴ 1/[A₀] = [1/(0.75 M)] - (1.57 x 10⁻⁵ M⁻¹s⁻¹)(28800 s) = 1.333 M⁻¹ - 0.4522 M⁻¹ = 0.8808 M⁻¹.
∴ [A₀] = 1/(0.0.8808 M⁻¹) = 1.135 M.
<em>So, the concentration of HI 8 hours earlier = 1.135 M.</em>
