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Anna007 [38]
3 years ago
14

What are ionic compounds typically composed of?

Chemistry
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer and explanation:

Ionic compounds are formed by elements with a considerable electronegativity difference. They are typically composed by an element of groups IA or IIA of the Periodic Table (with lower electronegativity, so it tends to lose electrons) and a other element of groups VIA or VIIA (with higher electronegativity, thus it tends to gain electrons). For example, KCl is formed by K (group IA), which loses one electron and forms the cation K⁺, and Cl (group VIIA) which gains the electron and forms the anion Cl⁻.

Mashcka [7]3 years ago
4 0

<span> </span><span>Ionic compounds are compound that contains ions held together by ionic bonds. They are made up of particles that are arranged in a repeating pattern. Ions are said to be packed in a regular crystalline structures in an arrangement with the least energy.</span>

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The egg white will represent the outer layer which is the we are located on!

Explanation:

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Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?
Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

y = 57.15 - 0.5x

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

<h3><u>If y = 3 what is x ?</u></h3>

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

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3 years ago
An elements what is its row in the periodic table
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Rows are periods, columns are groups

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50 POINTS!!!! Please Help I'm being timed and this would help so much! 50 POINTS!!!!
Studentka2010 [4]

Answer:

[H⁺] = 1.0 x 10⁻¹² M.

Explanation:

∵ [H⁺][OH⁻] = 10⁻¹⁴.

[OH⁻] = 1 x 10⁻² mol/L.

∴ [H⁺] =  10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.

∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.

∴ The solution is basic, since pH id higher than 7 and also the  [OH⁻] > [H⁺].

I think- IDK

5 0
3 years ago
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