Question

What mass of CO2 can be produced from the decomposition of 4.8 moles of Fe2(CO3)3?

Answer 1

Answer: 633.6 g of $CO_2$ can be produced from the decomposition of 4.8 moles of $Fe_2(CO_3)_3$

Explanation:

The balanced chemical equation for decomposition of $Fe_2(CO_3)_2$ is :

$Fe_2(CO_3)_2\rightarrow Fe_2O_3+3CO_2$

According to stoichiometry :

1 mole of $Fe_2(CO_3)_2$ produce = 3 moles of $CO_2$

Thus 4.8 moles of $Fe_2(CO_3)_2$ will rproduce=$\frac{3}{1}\times 4.8=14.4moles$  of $CO_2$

Mass of $CO_2=moles\times {\text {Molar mass}}=14.4moles\times 44g/mol=633.6g$

Thus 633.6 g of $CO_2$ can be produced from the decomposition of 4.8 moles of $Fe_2(CO_3)_3$