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lord [1]
3 years ago
15

Help me plz Identify the state of matter.

Chemistry
2 answers:
musickatia [10]3 years ago
8 0
Solids liquids and more
maw [93]3 years ago
8 0
Matter can exist in one of three main states solid liquid and gas
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The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

Learn more about Gibbs free energy here:

brainly.com/question/13765848

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7 0
2 years ago
The ------------- the temperature of an object, the faster the molecules vibrate.
labwork [276]
Higher, they have more energy so they move faster
3 0
3 years ago
Read 2 more answers
Please help ASAP
aev [14]

Answer:

1st one is correct, Igneous rocks are formed when molten rock cools and hardens.

5 0
3 years ago
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An air bubble with a radius of 2.5 cm at the bottom of a lake where the temperature is 5.4 0C and the pressure is 3.2atm rises t
olasank [31]

Answer:

3.8 cm

Explanation:

Given data

  • Initial pressure (P₁): 3.2 atm
  • Initial volume (V₁): 65 cm³

Volume of a sphere: V = 4/3 × π × r³ = 4/3 × π × (2.5 cm)³ = 65 cm³

  • Initial temperature (T₁): 5.4°C + 273.15 = 278.6 K
  • Final pressure (P₂): 1.0 atm
  • Final volume (V₂): ?
  • Final temperature (T₂): 25.0°C + 273.15 = 298.2 K

We can find the final volume using the combined gas law.

\frac{P_{1}\times V_{1}}{T_{1}} =\frac{P_{2}\times V_{2}}{T_{2}}\\\frac{3.2atm\times 65cm^{3} }{278.6K} =\frac{1.0atm\times V_{2}}{298.2K}\\V_{2}=223cm^{3}

The final radius of the bubble is:

V = 4/3 × π × r³

223 cm³ = 4/3 × π × r³

r = 3.8 cm

6 0
4 years ago
Select T/F for each of the following statements regarding Platinum Group Metals (PGMs):
otez555 [7]

Answer:

1) False 2) True 3) True 4) False 5) True

Explanation:

1) Platinum metal is corrosion resistant because of its less reactivity due to high ionization energy.

2) The intermediate layer of platinum group metals, are extremely dense because their crystal structures are close-packed and these atoms tend to offer numerous d electrons in a metallic bond, resulting in highly efficient packing of relatively heavy metal ions in the bulk metal.

3)  The extremely high bond strengths of the PGMs result in very low thermal expansion coefficients and extremely high elastic moduli.

4) Platinum came at number 10 in metals according to its electric conductivity property. There are other metals with different valence state that have high electric conductivity than platinum.

5) PGM's occurs at the concentration of 0.005 ppm in the earth's crust, resulting in extremely high prices and the price was 32 $ per gram in 2020.

5 0
3 years ago
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