<span>Lithium and Sodium both have their last elections added to s subshells. All alkali and alkali earth metals have their last electrons placed in s subshells.</span>
The balanced chemical reaction is written as:
Sb2S3 + 6HCl = 6SbCl<span>3 + 3H2S
We are given the amount of </span><span>antimony(III) sulfide to be used in the reaction. This is amount will be used for the calculations. We do as follows:
2.85 g Sb2S3 ( 1 mol / </span><span>339.715 g ) ( 6 mol SbCl3 / 1 mol Sb2S3 ) (</span> 228.13 g / mol ) = 11.48 g SbCl3
Answer:
0.40 L
Explanation:
Calculation of the moles of 
as:-
Mass = 51.24 g
Molar mass of = 171.34 g/mol
The formula for the calculation of moles is shown below:
Thus,
Volume = 1.20 L
The expression for the molarity is:
Thus,
Considering
Given that:
So,
<u>The volume of 0.24925M stock solution added = 0.40 L
</u>
Answer:
The final mass of sample is 1.3 g.
Explanation:
Given data:
Half life of H-3 = 12.32 years
Amount left for 15.0 years = 3.02 g
Final amount = ?
Solution:
First all we will calculate the decay constant.
t₁/₂ = ln² /k
t₁/₂ =12.32 years
12.32 y = ln² /k
k = ln²/12.32 y
k = 0.05626 y⁻¹
Now we will find the original amount:
ln (A°/A) = Kt
ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y
ln (3.02 g/ A) = 0.8439
3.02 g/ A = e⁰°⁸⁴³⁹
3.02 g/ A = 2.33
A = 3.02 g/ 2.33
A = 1.3 g
The final mass of sample is 1.3 g.
Explanation: Heat capacity is the amount of heat required to change the temperature of a ... Therefore, specific heat is measured in Joules per g times degree Celsius
