15 cookies burned because if you Turn
into a decimal then multiply it by 20 you get 15 and thats your answer.
Answer:
The correct order is:
a
c
d
b
Step-by-step explanation:
First, let's write 1/x in a convenient way for us:
a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.
Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:
c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.
Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:
d) Observe that x is the quotient of two integers with the denominator nonzero.
And that is the definition of rational, then we end with:
b) Hence x is rational.
Which is what we wanted to get.
The cosine function with the given characteristics is:
f(x) = 3*cos(x/2 - pi).
<h3>
How to get the cosine function?</h3>
The general cosine function is:
f(x) = A*cos(kx + p)
Where A is the amplitude and p is the phase, then we know that:
A = 3
p = -pi
Then we have:
f(x) = 3*cos(kx - pi)
And the period is equal to 4pi, then we must have that:
k*(x + 4pi) - pi = k*x - pi + 2pi
k = 1/2
Then the function is:
f(x) = 3*cos(x/2 - pi).
If you want to learn more about cosine functions:
brainly.com/question/4372174
#SPJ4
F (x)=3x+5
g (x)=x^2
g (x)-f (x)=(x^2)-(3x+5)
=x^2-3x-5