Answer:
This is because the acceleration of objects due to gravity is independent of the mass of the object and is constant for all objects, therefore, all objects fall with the same speed.
Explanation:
The weight of an object or force of gravity acting on an object on the surface of earth is a product of its mass and acceleration due to gravity.
Mathematically, w = mg
where, m=mass of the object; g = acceleration due to gravity
Also, from newton's law of gravitation, gravitational force on the object ,F = GMm/r²
where G is the gravitational constant; M is mass of Earth; m is mass of object; r is the distance of separation between the object and the center of mass of the earth which is approximately the radius of earth.
Since the weight of an object is equal to the force of gravitation acting on it
W = F
mg = GMm/r²
g = GM/r²
The expression above is that of the relationship between the force of gravity acting on a body on the earth's surface, the weight of that body and the acceleration due to gravity, g.
It can be seen that the acceleration due to gravity g is independent of the mass of the object. Therefore, the acceleration of objects due to gravity is constant for all objects and all objects fall with the same speed.
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Measurements made by Mariner 10 in 1974/75 showed that Mercury also has a magnetic field. According to the standard models, the dynamo effect in its metal core should generate similar field strengths to those on Earth.Mercury's magnetic field is 150 times weaker than that of our planet
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Answer:
Explanation:
Given that,
Current in wire are 1.3A and 3.15A
Distance between wire is d= 2.25cm
d = 2.25/100 = 0.025m
Force per unit length F/l?
Let us consider the field produced by wire 1 and the force it exerts on wire 2 (call the force F2).
The field due to I1 at a distance r is given to be
B1 = μo• I1 / 2πr
This field is uniform along wire 2 and perpendicular to it, and so the force F2 it exerts on wire 2 is given by
F=ILBsinθ
with sinθ=1:
F2=I2 • L •B1
By Newton’s third law, the forces on the wires are equal in magnitude, and so we just write F for the magnitude of F2. (Note that F1=−F2.) Since the wires are very long, it is convenient to think in terms of F/l, the force per unit length. Substituting the expression for B1 into the last equation and rearranging terms gives
F/l = μo• I1• I2 / 2πr
Where μo is constant
μo = 4π×10^7 Tm/A
Then,
F/l = μo• I1• I2 / 2πr
F/l = 4π ×10^-7 × 1.3×3.15/(2π×0.025)
F/l = 3.276×10^-5 N/m
the magnitude of the force per unit length that one wire exerts on the other is 3.276×10^-5 N/m
<span>2. Conduction transfers energy from one particle to another
This is true</span>
Answer:
18N
Explanation:
Mechanical Advantage of crowbar (lever), MA = Length of effort arm / Length of resistance arm
Therefore, MA = 28 cm / 4.2 cm = 6.667
Force required to pull the nail, F = Friction force / MA
ie, F = 120 N / 6.667 = 18 N