Answer:
5.88 Nm
Explanation:
Applying,
Moment(M) = Force(F)×perpendicular distance(d)
M = F×d.................... Equation 1
But,
F = mg.................. Equation 2
Where m = mass, g = acceleration due to gravity.
Substitute equation 2 into equation 1
M = mgd................. Equation 3
From the question,
Given: m = 3 kg, d = 20 cm = 0.2 m
Constant: g = 9.8 m/s²
Substitute these values into equation 3
M = 3×0.2×9.8
M = 5.88 Nm
Answer:
A) θmin= 76°.
Explanation:
Given that
Speed of cannonball = Vo
Lets take θ is the angle measure from horizontal
We know that
Range R
Height h
Given that h should be larger than R
h > R
θ >75.96°
So minimum angle should be 75.96° or 76°.
Answer:
Four; Two; One; Three
Explanation:
During a lab, a student tapes a ruler to a lab table and sets the ruler in motion. A laser detector pointed at the ruler records how many times the ruler vibrates back and forth in a period of time.
Pitch or frequency is defined as the number of cycles per unit time. We can calculate the pitch for each trials i.e.
Trial one, 
Trial two, 
Trial three, 
Trial four, 
Hence, the order of the trials from least to greatest pitch is :
Trial four, Trial two, Trial one and Trial three i.e. option (d) is correct.
Answer:
12m/s
Explanation:
x = (21 + 22t – 6 t2) m,
We can express change bin velocity as
dx/dt= -12t + 22
But Velocity is changing
interval t = 1 s
t = 4 s
at t = 1, x = 21 + 22(1) -6(1)^2
=37
at t = 4, x = 21 + 22(4) -6(4)^2
=13
Distance travelled at interval t = 1 s
t = 4 s
X2 - X1=13- 37. = - 24m
Velocity= displacement/ time
= 24/(3-1)=12 m/s
Answer:
Strong Positive Linear Line Correlation
Explanation:
According to the diagram, there is a strong positive linear line correlation between velocity and distance of galaxies. Hubble showed that galaxies are receding away from people with a velocity that is proportional to their distance from people more distant galaxies recede faster than nearby galaxies.
About the diagram: Velocity is the distance relation among extra-galactic nebulae. Radial velocities is corrected for solar motion, are plotted against distances estimated from involved stars and mean luminosities of nebulae in a cluster. The black discs and full line represent the solution for solar motion by using the nebulae individually; the circles and broken line represent the solution combining the nebulae into groups; the cross represents the mean velocity corresponding to the mean distance of 22 nebulae whose distances could not be estimated individually.
