Question

A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in feet is given by the polynomial −16t2 + 83t + 33, where t is the time in seconds. How high will the rocket be after 3 seconds?
a. 2586 feet
b. 234 feet
c. 138 feet
d. 105 feet

Answer 1

Answer:

c. 138 feet

Step-by-step explanation:

h(t) = −16t^2 + 83t + 33

At3 seconds

h(3) = -16(3^2) + 83(3) + 33

h(3) = -16(9) + 249 + 33

h(3) = -144 + 249 + 33

h(3) = 138

c. 138 feet