Why do scientifics look for patterns in the world?
1 answer:
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Answer:
The total amount of energy required is 25,515.2 J.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When a system absorbs (or gives up) a certain amount of heat, it can happen that:
- experience a change in its temperature, which involves sensible heat,
- undergoes a phase change at constant temperature, or latent heat.
To calculate the latent heat the formula is used:
Q = m. L
Where
- Q: amount of heat
- m: mass
- L: latent heat
To calculate sensible heat the following formula is used:
Q = m. c. ΔT
where:
- Q: amount of sensible heat
- m: body mass
- c: specific heat of the substance
- ΔT: temperature range
In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184 :
q1 = m*c*(Tfinal-Tinitial)
q1 = 10.0 g *(4.184 )* (100 - 35.0 C) = 2719.6 J
Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 :
q2 = m*(heat of vaporization)
q2 = 10.0 g*(2259.36 ) = 22593.6 J
Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02 :
q3 = m*c*(Tfinal-Tinitial)
q3 = 10.0 g*(2.02 )*(110-100 C) = 202 J
The total amount of energy can be calculated as:
Q= q1 + q2 + q3
Q= 2719.6 J + 22593.6 J + 202 J
Q=25,515.2 J
<u><em>The total amount of energy required is 25,515.2 J.</em></u>
Answer: -
The first compound is 3-Methylheptane.
The second compounds is 4-ethyl-3-methyl-4-propylheptane
The 3rd one is propanol.
The 4th one is 2-propanol.
The 5th one is methoxyethane
Answer:
0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl
Explanation:
The balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
Being:
- Mg: 24. 31 g/mole
- H: 1 g/mole
- Cl: 35.45 g/mole
the molar mass of the compounds participating in the reaction is:
- Mg: 24.31 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- MgCl₂: 24.31 g/mole + 2*35.45 g/mole= 95.21 g/mole
- H₂: 2*1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:
- Mg: 1 mole* 24.31 g/mole= 24.31 g
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
- H₂: 1 mole* 2 g/mole= 2 g
Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?
moles of H₂= 0.134
<u><em>0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl</em></u>