Answer:
162 kJ
Explanation:
The reaction given by the problem is:
- NBr₃(g) + 3 H₂O(g) → 3 HOBr(g) + NH₃(g) ∆H = +81 kJ
If we turn it around, we have:
- 3 HOBr(g) + NH₃(g) → NBr₃(g) + 3 H₂O(g) ∆H = -81 kJ
If we think now of HOBr and NH₃ as our reactants, then now we need to find out <u>which one will be the </u><em><u>limiting reactant</u></em> when we have 9 moles of HOBr and 2 moles of NH₃:
- When we have 1 mol NH₃, we need 3 mol HOBr. So when we have 2 moles NH₃, we need 6 moles HOBr. We have more than 6 moles HOBr so that's our <em>reactant in excess</em>, thus NH₃ is our limiting reactant.
-81 kJ is our energy change when there's one mol of NH₃ reacting, so we <u>multiply that value by two when there's two moles of NH₃ reacting</u>. The answer is 81*2 = 162 kJ.
Answer:
D. a program on a computer
Explanation:
The correct answer is that organic compounds get their name from its association with living organisms. The word "organic" means living. That's how they are related and that's how organic compounds get their name. I hope this answer helped you.
Answer:
sorry this is a kind of confusing question.
Explanation:
You may suppose you have a 0.1 M solution of NH3, from:
NH4Cl + NaOH > NH3 + H2O.
Then you can compute the pH from the concentration of NH3 and its pKb.
The concentration is high enough to use the simplified formula:
[OH] = sqr(Kb*conc)