Answer:
The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.
Explanation:
In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.
YF₃(s) ⇄ Y³⁺(aq) + 3 F⁻(aq)
I 0 0
C +S +3S
E S 3S
The solubility product (Ksp) is:
Ksp = [Y³⁺].[F⁻]³= S . (3S)³ = 27 S⁴
![S=\sqrt[4]{Ksp/27} =\sqrt[4]{8.62 \times 10^{-21} /27}=4.23 \times 10^{-6}M](https://tex.z-dn.net/?f=S%3D%5Csqrt%5B4%5D%7BKsp%2F27%7D%20%3D%5Csqrt%5B4%5D%7B8.62%20%5Ctimes%2010%5E%7B-21%7D%20%20%2F27%7D%3D4.23%20%5Ctimes%2010%5E%7B-6%7DM)
Mrna is a single strand but DNA is a double helix. (mrna is smaller)
Answer:
Explanation:
The subatomic particles called neutrons and protons are found in the nucleus of an atom and electrons travel around them
(4) 615 m
Explanation:
From the table we see that the speed of sound in air at 20 °C is 343 m/s. Knowing this we devise the following reasoning:
if the sound travel through the air 343 meters in 1 second
then the sound travel through the air X meters in 2.38 seconds
X = (2.38 × 343) / 1 = 816.35 meters
Learn more about:
speed of sound
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