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2 years ago

Question 1: Find the amount of the FICA deduction: $37890 annually.

Mathematics

1 answer:

Radda [10]2 years ago

7 0

Answer:

b....j..j.jm..e.e.e i didnt get it

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A leg of a right triangle measures 63 yards,

erma4kov [3.2K]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Y/2*4-10/x+6 where x=5 and y=16

Sliva [168]

(16)/(2)*4-(10)/(5)+6= 36

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3 years ago

Quick please , find the volume of the shape

Blizzard [7]

Answer:

7068.58 Cubic inch

Step-by-step explanation:

$V=\frac{2}{3} \pi r^{3} =\frac{2}{3} \pi 15^{3}=7068.58 in^{3}$

3 0

3 years ago

Describe using words in a sentence the transformations that must be applied to the graph of f to obtain thegraph of g(x) = -2 f(

grin007 [14]

we have

f(x)

and

g(x)=-2f(x)+5

step 1

First transformation

Reflection about the x-axis

f(x) -----> -f(x)

step 2

Second transformation

A vertical dilation with a scale factor of 2

-f(x) ------> -2f(x)

step 3

Third transformation

A translation of 5 units up

-2f(x) -------> -2f(x)+5

5 0

1 year ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago