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2 years ago

What 2 aspects of a force do scientists measure???

Physics

2 answers:

sdas [7]2 years ago

7 0

Answer: magnitude and direction

Explanation:They are the two aspects of force that scientists measure

sveticcg [70]2 years ago

6 0

Answer:

Explanation:

Force is a VECTOR QUANTITY which means it is DEFINED by its MAGNITUDE AND DIRECTION

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The rate of change of momentum of a body free falling under gravity is equal to its? A. Velocity B. kinetic energy C. power D. w

jolli1 [7]

Answer:

weight

Explanation:

this is because of the lighter the object the faster it will be affected

7 0

2 years ago

Read 2 more answers

Objects 1 and 2 attract each other with a electrostatic force

daser333 [38]

Electrostatic force changes like the inverse square of the distance (just like gravity).

If you double the distance, you change the force to 1/4 of what it used to be.

After the move, Objects 1 and 2 attract each other with a force of (18/16) = 1.125 units .

6 0

2 years ago

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Researchers in the Antarctic measure the temperature to be -32°F. What is this temperature on the following scales?(a) the Celsi

Illusion [34]

Answer:

a) -35.6°C

b) 237.4 K

Explanation:

To convert temperature from degree celsius to degree fahrenheit, use the formula below:

$T_c=\frac{5}{9}(T_f-32)$

a) Therefore to convert -32°F to celsius, substitute it into the celsius

$\begin{gathered} T_c=\frac{5}{9}(-32-32) \\ \\ T_c=\frac{5}{9}(-64) \\ \\ T_c=-35.6^0C \end{gathered}$

b) To covert to the Kelvin scale, use the formula below

$\begin{gathered} T_k=T_c+273 \\ \\ T_k=-35.6+273 \\ \\ T_k=237.4K \\ \end{gathered}$

8 0

9 months ago

A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication

koban [17]

Answer:

r = 4.24x10⁴ km.

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

$\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}$

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>

From equation (1), r₁ is:

$r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}$

$r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}$

$r_{1} = 4.24 \cdot 10^{4} km$

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

3 0

3 years ago

A ship travels with velocity given by 12, with current flowing in the direction given by 11 with respect to some co-ordinate axe

nataly862011 [7]

Answer:

$v_x = 11.78 m/s$

Explanation:

Velocity of the ship is given as

$v = 12 units$

the direction of the velocity of the ship is making an angle of 11 degree with the current

so we will have two components of the velocity

1) along the direction of the current

2) perpendicular to the direction of the current

so here we know that the component of the ship velocity along the direction of the current is given as

$v_x = v cos\theta$

$v_x = 12 cos11$

$v_x = 11.78 m/s$

7 0

2 years ago