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SpyIntel [72]
3 years ago
13

A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the train

Physics
2 answers:
Eddi Din [679]3 years ago
8 0

Explanation:

A=v-u/t

A= 6- 28/4

A= 5.5m/s2

s= ut+ 1/2 at^2

s = 28 * 4+ 1/2 * 5.5 * 4^2

s = 112 + 1/2 * 5.5 * 16

s = 112 + 5.5* 8

s= 112 + 44

s = 156m

adell [148]3 years ago
7 0
The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry

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A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,
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Answer:

v = 7934.2 m/s

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So we will have

-\frac{GMm}{r} + \frac{1}{2}mv_0^2 = -\frac{GMm}{R} + \frac{1}{2}mv^2

now we know that

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3 years ago
The flywheel of an engine has moment of inertia 2.50 kg m2 about its rotation axis. What constant torque is required to bring it
MrRissso [65]

Answer:

Explanation:

From the question we are told that

   The moment of inertia is  I = 2.50 \ kg \cdot m^2

    The final  angular speed is w_f =  400 rev/min  =  \frac{400 * 2\pi}{60}  = 41.89 \ rad/s

     The time taken is  t =  8.0 s

      The initial angular speed is  w_i  =  0\ rad/s

Generally the average angular acceleration is mathematically represented as

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