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noname [10]
3 years ago
5

If the mass of the body is tripled and its velocity becomes doubled, then the linear momentum of the body will​

Physics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

don't know I is not am studnt

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The difference between an experimental value and an accepted value is
likoan [24]

Answer:

HERE'S MY UNDERSTANDING OF THE DIFFERENCE

3 0
3 years ago
A satellite orbits the Earth in an elliptical orbit. At perigee its distance from the center of the Earth is 22500 km and its sp
aleksley [76]

Answer:

6.09294\times 10^{24}\ kg

Explanation:

K = Kinetic energy

v_p = Perigee speed = 4280 m/s

v_a = Apogee speed = 3990 m/s

r_p = Perigee Distance = 22500000 m

r_a = Apogee Distance = 24100000 m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Earth

m = Mass of satellite

In this system the kinetic and potential energies are conserved

K_p+P_p=K_a+P_a\\\Rightarrow \frac{1}{2}mv_p^2-\frac{GMm}{r_p}=\frac{1}{2}mv_a^2-\frac{GMm}{r_a}\\\Rightarrow \frac{1}{2}m(v_p^2-v_a^2)+GMm\left(\frac{1}{r_a}-\frac{1}{r_p}\right)=0\\\Rightarrow M=\frac{v_a^2-v_p^2}{2G}\times \left(\frac{1}{r_a}-\frac{1}{r_p}\right)^{-1}\\\Rightarrow M=\frac{3990^2-4280^2}{2\times 6.67\times 10^{-11}}\times \left(\frac{1}{24100000}-\frac{1}{22500000}\right)^{-1}\\\Rightarrow M=6.09294\times 10^{24}\ kg

The mass of the Earth is 6.09294\times 10^{24}\ kg

3 0
4 years ago
What are saturated and non saturated vapour? ​
Elodia [21]

Answer:

A saturated vapour is one that is in balance with its own liquid. Space is considered to be unsaturated if it contains fewer vapours than the maximum amount it can retain at a given temperature. Saturated vapour pressure is unaffected by volume, although it rises as temperature rises.

Explanation:

8 0
3 years ago
Please explain why<br>True or False<br>Burning paper is a formation of a precipitate<br>​
Kruka [31]
False because paper is tem
5 0
3 years ago
What affect does doubling the net force have on the acceleration of the object (when
Triss [41]
<h3>Answer: The acceleration doubles</h3>

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

8 0
3 years ago
Read 2 more answers
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