Answer:
so height is 0.1283 m
Explanation:
given data
height = 28 cm
diameter = 11 cm
cross-sectional area = 1.55 cm2
water flow rate = 2.46×10^−4 m3/s
to find out
How high will the water in the bucket rise
solution
we know that here
potential energy = kinetic energy
mgh = 1/2 mv²
multiply both sides by the 2 and we get
2mgh=mv²
solve it we get
√(2gh) = v ....................1
h = v²/2g ...............2
and
flow rate = A V
2.46×10^−4 = V 1.55×10^−4
V = 1.5870 m/s
so from 2
h = v²/2g
h = 1.5870²/ 2(9.81)
h = 0.1283 m
so height is 0.1283 m
Water freezes at zero degrees Celsius (32 degrees Fahrenheit). The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another. ... This is what happens when the ice cube (a solid) turns into water (a liquid)
Answer:
1100Joules
Explanation:
Workdone = force x distance
Force= 500N
Distance = 2.2m
So, workdone = 500 x 2.2
= 1100Joules
Answer:
Explanation:
According to heisenberg uncertainty Principle
Δx Δp ≥ h / 4π , where Δx is uncertainty in position , Δp is uncertainty in momentum .
Given
Δx = 1 nm
Δp ≥ h /1nm x 4π
≥ 6.6 x 10⁻³⁴ / 10⁻⁹ x 4 π
≥ . 5254 x ⁻²⁵
h / λ ≥ . 5254 x ⁻²⁵
6.6 x 10⁻³⁴ /. 5254 x ⁻²⁵ ≥ λ
12.56 x 10⁻⁹ ≥ λ
longest wave length = 12.56 n m
Answer:
1.) Time t = 3.1 seconds
2.) Height h = 46 metres
Explanation:
given that the initial velocity U = 30 m/s
At the top of the trajectory, the final velocity V = 0
Using first equation of motion
V = U - gt
g is negative 9.81m/^2 as the object is going against the gravity.
Substitute all the parameters into the formula
0 = 30 - 9.81t
9.81t = 30
Make t the subject of formula
t = 30/9.81
t = 3.058 seconds
t = 3.1 seconds approximately
Therefore, it will take 3.1 seconds to reach to reach the top of its trajectory.
2.) The height it will go can be calculated by using second equation of motion
h = ut - 1/2gt^2
Substitutes U, g and t into the formula
h = 30(3.1) - 1/2 × 9.8 × 3.1^2
h = 93 - 47.089
h = 45.911 m
It will go 46 metres approximately high.
