Answer:
24.5 N
Explanation:
Draw a free body diagram of the picture. There are four forces:
Weight force mg pulling down.
Friction force Nμ pushing up.
Normal force N pushing left.
Applied force F pushing right.
Sum of the forces in the y direction:
∑F = ma
Nμ − mg = 0
N = mg / μ
Sum of the forces in the x direction:
∑F = ma
F − N = 0
F = N
Substitute and solve:
F = mg / μ
F = (1.5 kg) (9.8 m/s²) / (0.6)
F = 24.5 N
I think it's D)!!!!!!!!!!
Answer:
resultant force=16N→(TOWARDS THE DIRECTION OF 8N)
Explanation:
resultant force=8N+13N-5N
=16N→(TOWARDS THE DIRECTION OF 8N)
Weight in water = mass of block - mass of volume of displaced water
W=1/2cvsqr....1/2*25*10^-6*144
0.0000125*144=0.0018=18micro farad
