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kotegsom [21]
3 years ago
6

Find the lower quartile of the data set 593,588,540,434,420,398,390,375

Mathematics
2 answers:
pantera1 [17]3 years ago
7 0
Lower quartile is 394
Galina-37 [17]3 years ago
6 0

First Quartile Q1 = 394

Second Quartile Q2 = 427

Third Quartile Q3 = 564

Interquartile Range IQR = 170

Median = Q2 x˜ = 427

Minimum Min = 375

Maximum Max = 593

Range R = 218

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PLEASE HELP!!!!!
Zielflug [23.3K]
Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.



Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}

Let's plug this into this form first:
y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55

Now, let's make it into Standard Form.
y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
\boxed{f(x) = 85x + 55}

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
5 0
3 years ago
GEOMETRY PEOPLE PLEASE HELP ME!!!!!!!!!!!!!!!!! I WILL GIVE BRAINLIEST!
IrinaVladis [17]

\Delta KLJ\sim\DeltaNPM (AAA) Corresponding angles are congruent.

Therefore, the sides of the triangles are proportional:

\dfrac{4x-4}{20}=\dfrac{30}{25}    cross multiply

25(4x-4)=(20)(30)    use distributive property

(25)(4x)+(25)(4)=600\\\\100x+100=600    subtract 100 from both sides

100x=500     divide both sides by 100

x=5

--------------------------------------------------------------------------------------------

\Delta PQR\cong\Delta STU (SAS)

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Therefore we have the equation:

3y-2=y+4\qquad|+2\\\\3y=y+6\qquad|-y\\\\2y=6\qquad|:2\\\\y=3

The perimeter of △PQR:

P=4+6+3y-2=8+3y

Substitute the value of y to the expression:

P=8+3(3)=8+9=17\ ft

7 0
3 years ago
:BfJBFLbobafofbudbnmb ggjpbpgbpgsbgubpbgbnopgnpgpngnp ya know
nadya68 [22]

Answer:

jdasoiagkjevlaagehvdlnkaaaaaaajajeghand

Step-by-step explanation:

5 0
3 years ago
You have a total of 45 dimes and quarters. You have 3 more quarters than dimes. Which system of equations can you use to find th
lina2011 [118]

Let's call dimes x and the quarters x+3 since we have 3 more of them.

x+x+3=45

2x=42

x=21

we have 21 dimes and 23 quarters

21*0.10=2.1

23*0,25=5.98

if we add those together it equals 8.08

5 0
4 years ago
Read 2 more answers
4 = 2/3 ( x + - 12 )
hichkok12 [17]

Answer:

18 = x

Step-by-step explanation:

4 = 2/3 ( x + - 12 )

4 = 2/3x - 8

+8          + 8

<u>12 = 2/3x</u>

2/3   2/3

18 = x


Sorry if I'm incorrect...

3 0
3 years ago
Read 2 more answers
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