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postnew [5]
3 years ago
6

Please need help on math quiz!!! Zoom in to see better.

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

It should be A

Step-by-step explanation:

120 around b then 45 around a

120 clockwise is positive

45 counterclockwise is negative

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Help i'll make you the brainliest
9966 [12]

Answer:

D) b = \frac{S-2ac}{2a + 2c}

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = \frac{S-2ac}{2(a + c)}

Finally, multiply out the denominator:

b = \frac{S-2ac}{2a + 2c}

7 0
3 years ago
If m< BOE = 130 degrees and m< cob = 80 degrees
hjlf

Answer:

then what?

Step-by-step explanation:

do we have to find the angle?

all I know is every right triangle is equal to 90°

6 0
3 years ago
Take 2y 2 - 3y - 5 from y 3 - 6y 2 + 5y. Select the correct answer.
NNADVOKAT [17]

Answer:

y^3-8y^2+8y+5

Step-by-step explanation:

Take one polynomial from the other means to perform the sub.traction of them. Recall that it is better to use grouping symbols when subtracting polynomials, so we get the signs right when combining like terms:

The indicated subtraction is: y^3-6y^2+5y - (2y^2-3y-5)

Make sure that before removing the grouping symbol (parenthesis) that is preceded by a negative sign, we change the signs of every term inside it. Then combine like terms to get the final answer:

y^3-6y^2+5y - (2y^2-3y-5)=\\=y^3-6y^2+5y-2y^2+3y+5=\\=y^3-6y^2-2y^2+5y+3y+5=\\=y^3-8y^2+8y+5

Which is the last option shown in the question

3 0
3 years ago
If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
krok68 [10]

Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

⇒ Tanx = {\frac{7}{25}}(\frac{25}{24} )

⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

7 0
4 years ago
Need help asap! Show work if you can, it’s completely ok if you don’t tho
Savatey [412]
Its A) -67
plug the m and n values into the function and solve using pemdas.
5(-7)-2(-7+3)^2
-35-2(-4)^2
-35-2(16)
-35-32
-67
8 0
4 years ago
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