Answer:
a. 1 pair of pants is $6
b. $66 for 11 pairs of pants
a. 18/3 = 6
b. 6 × 11 = 66
You can find one the picture I send
Answer:
= (3t+2)(3t-2)(3t-4)
Step-by-step explanation:
Given the expression 27t^3 - 36t^2 - 12t + 16
On factoring:
(27t^3 - 36t^2) - (12t + 16)
= 9t²(3t-4)-4(3t-4)
= (9t²-4)(3t-4)
factoring 9t²-4
9t²-4 = (3t)² - 2²
From different of two square, a²-b² = (a+b)(a-b)
Hence (3t)² - 2² = (3t+2)(3t-2)
= (9t²-4)(3t-4)
= (3t+2)(3t-2)(3t-4)
Hence the factored form of the expression is (3t+2)(3t-2)(3t-4)
So, the function is obviously shifted up by 1 so it rules out A and B, and we also see that the period is 4pi rather than 2pi, and using the fact that:

Now that we know our b value, we see that the correct answer would be C.
Answer:
x=2 (-7 , then -5 for the drag part)