Answer:
fruiwehwe
Step-by-step explanation:hjhenrefen
The derivative of a variable raised to exponent of n, x^n is equal to the product of n and x raised to exponent of n-1.
d(x^n) = (n)(x^n-1)
So, from the given
d(9x + 5) = (1)(9x^1-0) + 5(0)
= 9
The given value of x is irrelevant to this item because the derivative does not contain any variable x.
Answer:
0.573 m
Step-by-step explanation:
a. To find the depth, x, we first solve the differential equation to find the expression for I
dI/dx = (-1.21)I
dI = (-1.21)Idx
dI/I = -1.21dx
Integrating both sides, we have
∫dI/I = ∫-1.21dx
㏑I = -1.21x + C
I = exp(-1.21x + C)
I = exp(-1.21x)exp(C) Let exp(C) = A
I =Aexp(-1.21x)
when x = 0, I = L. Substituting these into the equation, we have
L = Aexp(-1.21 × 0)
L = Aexp(0)
L = A
So, I = Lexp(-1.21x)
we want to find x when I = L/2.
So, L/2 = Lexp(-1.21x)
1/2 = exp(-1.21x)
-1.21x= ㏑(1/2)
-1.21x= -㏑2
x = -㏑2/-1.21
x = 0.693/1.21
x = 0.573 m
Answer:
Water (H2O)
Step-by-step explanation:
When hydrocarbons undergo combustion reactions (I.e reactions with oxygen) carbon (iv) oxide and water are usually produced.
In this case, the only difference is the numbe of moles between the product and reactant
Equation of reaction;
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Reactants:
1. Ethane = C₂H₆
2. Oxygen = O₂
Product:
1. Carbon(iv) oxide = CO₂
2. Water = H₂O
Hello,
x²/25+y²/9=1
a=5, b=3 c²=a²-b²=25-9=16=4²
Foci are (0,4) and (0,-4)
Answer C
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