The systems will intersect at (1,-4), and i think the system has infinite solutions (not sure)
The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>
The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
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Answer:
x = 2 and x = -1
Step-by-step explanation:
The zeroes of the function are found by setting g(x) equal to 0:
g(x) = (x - 2)(3x + 3) = 0
By the Zero Product Property, in order for this equation to be equal to 0, each of (x - 2) or (3x + 3) or both has to equal 0. So, set each equal:
x - 2 = 0
x = 2
3x + 3 = 0
3x = -3
x = -3/3 = -1
The zeroes are thus x = 2 and x = -1.
<em>~ an aesthetics lover</em>