Answer:
136.5886g of NH3
Explanation:
N2 + 3H2 = 2NH3
The mass of the N2 = 4.01
3H2 has a 2/1 ratio
This means the mass of 3H2 is twice as much as N2.
NH3= 2*N2 = 2*4.01 = 8.02 of NH3
Then, by multiplying the mass by MX (17.031)
8.02*17.031=136.5886g can be produced. Round it if needed.
Molas mass C6H12O6 = 180.15 g/mol
1 mole C6H12O6 -------------- 180.15 g
?? molesC6H12O6 ------------ 3.10x10⁻³ g
3.10x10⁻³ x 1 / 180.15 => 0.00001720 moles
1 mole ------------------------- 6.02x10²³ molecules
0.00001720 moles ---------- ??
0.00001720 x (6.02x10²³) / 1 => 1.035x10¹⁹ molecules
It is because C4 compromises on water loss and CAM compromises on photorespiration. and Both minimize photorespiration but expend more ATP during carbon fixation.
Answer:
To stop restoring equilibrium to the system