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love history [14]
3 years ago
8

The alternative pathways of photosynthesis using the c4 or cam systems are said to be compromises. why?

Chemistry
2 answers:
frosja888 [35]3 years ago
7 0
 It is because C4 compromises on water loss and CAM compromises on photorespiration. and Both minimize photorespiration but expend more ATP during carbon fixation. 
pentagon [3]3 years ago
3 0

Both minimize photorespiration but expend more ATP during carbon fixation is the correct answer on MasteringBio.

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Please help!!! ill mark u brainly
Musya8 [376]

Answer: I say it is A sorry if I'm incorrect

Explanation:

8 0
4 years ago
In an aqueous solution, 42% of a substance dissociates to release hydronium ions. Which of the following statements is true for
const2013 [10]

Answer: The statement it is a weak acid is true for the substance.

Explanation:

An acid that dissociates completely when dissolved in water to give hydrogen (H^{+}) or hydronium (H_{3}O^{+}) ions is called a strong acid.

For example, HCl is a strong acid.

HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}

An acid that dissociates partially or weakly when dissolved in water to given hydrogen or hydronium ions is called a weak acid.

For example, CH_{3}COOH is a weak acid.

CH_{3}COOH \rightleftharpoons CH_{3}COO^{-} + H_{3}O^{+}

A strong base is a base which when dissolved in water then it dissociates completely to give hydroxide ions.

For example, NaOH is a strong acid.

A weak base is a base which when dissolved in water then it dissociates partially or weakly to give hydroxide ions.

For example, NH_{3} is a weak base.

Hence, in an aqueous solution where 42% of a substance dissociates to release hydronium ions shows that the dissociation is less than 50%. This means that substance is dissociating weakly so, it is a weak acid.

Thus, we can conclude that the statement it is a weak acid is true for the substance.

5 0
3 years ago
Select the two chemical reactions that adhere to the law of conservation of matter.
rodikova [14]

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6 0
2 years ago
How to solve determine the final temperature when 450.2 grams of aluminum at 95.2°c is placed in an insulated calorimeter with 6
Pavlova-9 [17]

To solve this, we simply equate the change in enthalpy for the two substances since heat gained by water is equal to heat lost of aluminum. We know that the heat capacity of aluminum is 0.089 J/g°C and that of water is 4.184 J/g°C. Therefore:

450.2 (95.2 - T) (0.089) = 60 (T – 10) (4.184)

3,814.45456 – 40.0678 T = 251.04 T – 2,510.4

291.1078 T = 6,324.85456

<span>T = 21.7°C</span>

8 0
3 years ago
If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o
ddd [48]

Answer : The mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol

Now we have to calculate the moles of O_2 in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

V\propto n

or,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 6.21 L

V_2 = final volume of gas = 30.3 L

n_1 = initial moles of gas = 0.16 mol

n_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}

n_2=0.781mol

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

Molar mass of O_2 = 32 g/mol

\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g

Therefore, the mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0
3 years ago
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