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love history [14]
3 years ago
8

The alternative pathways of photosynthesis using the c4 or cam systems are said to be compromises. why?

Chemistry
2 answers:
frosja888 [35]3 years ago
7 0
 It is because C4 compromises on water loss and CAM compromises on photorespiration. and Both minimize photorespiration but expend more ATP during carbon fixation. 
pentagon [3]3 years ago
3 0

Both minimize photorespiration but expend more ATP during carbon fixation is the correct answer on MasteringBio.

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What are the elements of PCl5 and the name
prisoha [69]
Phosphorus, Chlorine. The IUPAC name is Phosphorus pentachloride

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3 years ago
According to the National Institute of Health, ventricular tachycardia is a fast, regular beating of the ventricles that may las
jarptica [38.1K]

Answer:

1 makes the most sense

Explanation:

There is no way blood pressure will be decreased especially if your ventricles are erratically contracting for a long period of time. So 3 and 4 are out. And you said number 2 is wrong so my finally answer is 1.

3 0
3 years ago
How many total atoms are in 0.330 g of P2O5?
hichkok12 [17]
A) covert 0.330g to moles by dividing by molar mass of P2O5 .. Let's call this Y moles
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So here it is 6.02 x 10^23 x Y molecules
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4 0
3 years ago
What kind of water is found in littoral zone of a lake?
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8 0
2 years ago
A 60.0 g block of iron that has an initial temperature of 250. °C and 60.0 g bloc of gold that has an initial temperature of 45.
Maslowich

Answer:

The final temperature at the equilibrium is 204.6 °C

Explanation:

Step 1: Data given

Mass of iron = 60.0 grams

Initial temperature = 250 °C

Mass of gold = 60.0 grams

Initial temperature of gold = 45.0 °C

The specific heat capacity of iron = 0.449 J/g•°C

The specific heat capacity of gold = 0.128 J/g•°C.

Step 2: Calculate the final temperature at the equilibrium

Heat lost = Heat gained

Qlost = -Qgained

Qiron = -Qgold

Q=m*c*ΔT

m(iron) * c(iron) *ΔT(iron) = -m(gold) * c(gold) *ΔT(gold)

⇒with m(iron) = the mass of iron = 60.0 grams

⇒with c(iron) = the specific heat of iron = 0.449 J/g°C

⇒with ΔT(iron)= the change of temperature of iron = T2 - T1 = T2 - 250.0°C

⇒with m(gold) = the mass of gold= 60.0 grams

⇒with c(gold) = the specific heat of gold = 0.128 J/g°C

⇒with ΔT(gold) = the change of temperature of gold = T2 - 45.0 °C

60.0 *0.449 * (T2 - 250.0) = -60.0 * 0.128 * (T2 - 45.0 )

26.94 * (T2 - 250.0) = -7.68 * (T2 - 45.0)

26.94T2 - 6735 = -7.68T2 + 345.6

34.62T2 = 7080.6

T2 = 204.5 °C

The final temperature at the equilibrium is 204.6 °C

5 0
3 years ago
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