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3 years ago

-3x^2-12x-3 How do I factor this function?

Mathematics

1 answer:

Tpy6a [65]3 years ago

6 0

Answer:

Step-by-step explanation:

Take the -3 out:

-3(x^2 +4x+1)

It's best to use the quadratic formula in this case:

(-b±√b²-4ac)/2a

where a =1, b =4, c=1

(-4 ±√16 -4)/2(1)

when you do (-4+√16 -4)/2(1), you will get -2+√3 = -0.2679..

when you do (-4-√16 -4)/2(1), you will get -2-√3= -3.732..

So, the factored form would look like:

-3(x-2+√3)(x-2-√3)

Hope this helps!

Would really appreciate the brainliest if you think i helped!

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Write an equation in slope intercept form that describes a line with a slope of 3 and containing the point (5,-1)

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

Equation of line with a given slope of a and containing a given point (x₀, y₀):

y - y₀ = a(x - x₀)

a = 3, x₀ = 5, y₀ = -1

So:

y - (-1) = 3(x - 5)

y = 3x - 15 - 1

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3 years ago

What is the additive version of the complex number -8+3i

Lana71 [14]

Answer:

8-3i

Step-by-step explanation:

The complex additive inverse is the number we need to add so that we get zero. It is the negative of the number.

a + bi is –(a + bi) = –a – bi.

a+bi + (-a+-bi) = a-a + bi-bi = 0

The complex additive invers of -8+3i is

-(-8+3i)

Distribute the negative

8 -3i

6 0

3 years ago

Help (fraction) problem :(

Nastasia [14]

Answer:

it's 8 4/6 because you have to make the denominator all 6 so you would have to mutiply the bottom and do the same for the top keep the whole number the same and then add it all up you'll get 8 4/6

4 0

3 years ago

Read 2 more answers

On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line

NikAS [45]

Answer:

the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{2-(-4)}{4-(-2)} = 1$

Now, using slope intercept form ( $y = mx+c$ ) of a line, we can write the equation of line parallel to AB:

$y =(1)x+c \Rightarrow y = x+c$

Now, putting the point P(0,4) to find c:

$4 = 0 +c \Rightarrow c = 4$

So, the equation is $\bold{y=x+4}$

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3), (–2, 2) and (–5, –1)

8 0

3 years ago

Read 2 more answers

QUICK I NEED HELP PLEASE!

seraphim [82]

Assuming you meant is $- \frac{3}{5} x+ \frac{1}{5} \ \textgreater \ 720$

The answer would be :
$- \frac{3}{5} x\ \textgreater \ 719.8$

$x \ \textless \ \frac{719.8}{ \frac{-3}{5} }$
$x\ \textless \ 719.8 *( \frac{-5}{3} )$
$x\ \textless \ \frac{-3599}{3}$

Hope this helps !

Photon

However, your equation seems weird :o

8 0

3 years ago