x^a / x^b = x^(a-b)
so here its x^( (5/6)- (1/6) )
= x^ 4/6 or ^2/3
128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
21,000
Step-by-step explanation:
This is more of straightforward multiplication, so I cannot explain much! If you want me to try to do more, then just comment.
(7 * 10 * 5) * (3 * 10 * 2)
= (70 * 5) * (30 * 2)
= (350) * (60)
= 21,000
Thusly, in standard form, the equation given is 
.
Hope this helps! (:
