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sesenic [268]
3 years ago
14

-3x^2-12x-3 How do I factor this function?

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

Answer:

Step-by-step explanation:

Take the -3 out:

-3(x^2 +4x+1)

It's best to use the quadratic formula in this case:

(-b±√b²-4ac)/2a

where a =1, b =4, c=1

(-4 ±√16 -4)/2(1)

when you do (-4+√16 -4)/2(1), you will get  -2+√3 = -0.2679..

when you do (-4-√16 -4)/2(1), you will get -2-√3= -3.732..

So, the factored form would look like:

-3(x-2+√3)(x-2-√3)

Hope this helps!

Would really appreciate the brainliest if you think i helped!

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-3 +3(n+8)= 2(1 + 6n) - 8
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Answer:

3 =n

Step-by-step explanation:

-3 +3(n+8)= 2(1 + 6n) - 8

Distribute

-3 +3n +24 = 2 +12n -8

Combine like terms

21+3n = 12n -6

Subtract 3n from each side

21+3n-3n = 12n-3n -6

21 = 9n -6

Add 6 to each side

21+6 = 9n-6+6

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27/9 = 9n/9

27/9 =n

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Answer:

Step-by-step explanation:suppose

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So here are the rules of horizontal asymptotes:

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