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Hitman42 [59]
3 years ago
15

Question #

Chemistry
2 answers:
kolezko [41]3 years ago
7 0

Answer:

Carbon dioxide

Explanation:

I’ve done this perfore

stira [4]3 years ago
4 0

Answer:

Respiration: Uses Oxygen water to Break Down Food for Energy.

Explanation:

Let me know if this is right or wrong :) if this is late i'm sorry

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How many moles of CO2 are produced from the combustion of 6.40 mol c2h8?
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12.8 mole of CO2 from the combustion
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Identify the reactants in the equation: 6C0, + 6H2O - CHUO+ 60,
Effectus [21]

Answer:

The correct answer is d. 6H20 + 6CO2.

The reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

Explanation:

5 0
3 years ago
6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?
Eddi Din [679]

Answer:

 12120 g  +    O2        =    15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2.  calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) =  ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) =  ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 %  = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

3 0
3 years ago
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