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vfiekz [6]
1 year ago
8

Urgent!!!

Chemistry
1 answer:
Yakvenalex [24]1 year ago
6 0

The specific heat of the metal, given the data from the question is 0.60 J/gºC

<h3>Data obtained from the question </h3>

The following data were obtained from the question:

  • Mass of metal (M) = 74 g
  • Temperature of metal (T) = 94 °C
  • Mass of water (Mᵥᵥ) = 120 g
  • Temperature of water (Tᵥᵥ) = 26.5 °C
  • Equilibrium temperature (Tₑ) = 32 °C
  • Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
  • Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of gold can be obtained as follow:

According to the law of conservation of energy, we have:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Thus, the specific heat capacity of the metal is 0.60 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

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