Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints
take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3
test entpoints
f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190
the min is at x=3 and max is at x=-2
Answer:
20.94021
Step-by-step explanation:
mark me brainlist
Answer:
Step-by-step explanation:
you have t as a total amount of the whole class.
f= did not pass and you place the total number next to it like this; f/t represents that group. You continue this in your workings.
f/t = probability failed.
p/t = probability passed
c/t = probability completed
dc/t = probability did not complete
and draw a tree.
The random would be either of these, we know there s a possibility of 1/4 but the odds stay central. We look for a new way after this data is converted as a fraction and show these fractions as your answer.
