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scoundrel [369]
2 years ago
6

Please help I'm lost

Mathematics
1 answer:
cupoosta [38]2 years ago
5 0

Answer:

x=3

y=2

z=-3

Step-by-step explanation:

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A cyclist travels 4 miles in 20 minutes and then a further 6 miles in 30 minutes without stopping. Calculate the cyclist's avera
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Answer:

11 miles per hr because 10 miles took 50 minutes so add 1 mile and it is 1hr. Which is 11 miles per hr

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2 years ago
Two angles of a quadrilateral measures 20° and 50° the other two angles are in a ratio of 4:15 what are the measures of those tw
AURORKA [14]

Answer:

Solve for Y, then use either equation to find X

Step-by-step explanation:

360-275-20=65ratio 3:103x+10x=6513x=65x=55*3=15° and 5*10=50°15° and 50° are the other two angles

6 0
2 years ago
Suppose that replacement times for washing machines are normally distributed with a mean of 9.4 years and a standard deviation o
Nezavi [6.7K]

Using the normal distribution, it is found that the replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are, respectively, given by \mu = 9.4, \sigma = 2.

The desired value is the 82nd percentile, which is X when Z = 0.915, hence:

Z = \frac{X - \mu}{\sigma}

0.915 = \frac{X - 9.4}{2}

X - 9.4 = 0.915(2)

X = 11.23

The replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

More can be learned about the normal distribution at brainly.com/question/24663213

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1 year ago
Lily likes to collect records. Last year she had 10 records in her collection. Now she has 11 records,
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Find the 5th term sequence defined as : a(n)=(n+3)∧n-1
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a_n=(n+3)^n-1\\\\a_1=(1+3)^1-1=4-1=3\\\\a_2=(2+3)^2-1=5^2-1=25-1=24\\\\a_3=(3+3)^3-1=6^3-1=216-1=215\\\\a_4=(4+3)^4-1=7^4-1=2401-1=2400\\\\a_5=(5+3)^5-1=8^5-1=32768-1=32767
5 0
3 years ago
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