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navik [9.2K]
3 years ago
5

Can someone help me please

Chemistry
1 answer:
ozzi3 years ago
4 0
YeS I may help





Uhhhhh

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Some instant cold packs contain ammonium nitrate and a separate pouch of water. When the pack is activated by squeezing to break
KIM [24]

Answer:

a) Endothermic

b) T₂ = 53.1 ºC

Explanation:

a) We are told that when the ammonium nitrate dissolves in water the pack gets cold so the system is absorbing heat from the surroundings and by definition it  is an endothermic process.

b) Recall that the heat, Q, is given by the formula:

Q = mcΔT    where  m is the mass of water,

                                 c is the specific heat of water, and

                                 ΔT is the change in temperature

We can determine the value for Q since we are given the heat of solution for the ammonium nitrate. From there we can calculate ΔT and finally answer our question.

Molar mass NH₄NO₃ = 80.04 g/mol

moles NH₄NO₃ = 50.0 g/ 80.04 g/mol = 0.62 mol

Q = 25.4 kJ/mol x 0.62 mol = 15.87 kJ = 15.87 kJ x 1000 J = 1.59 x 10⁴ J

Q = mcΔT ⇒ ΔT = Q/mc

ΔT = 1.59 x 10⁴ J/ (135 g x 4.184 J/gºC ) = 28.1 ºC

T₂- T₁ = ΔT ⇒ T₂ = ΔT  + T₁  = 28.1 ºC +25.0 ºC = 53.1 ºC

5 0
4 years ago
State two example of how engineers use their knowledge of atoms to create new technologies?( I am giving you high points for thi
Eduardwww [97]

The correct answer to this open question is the following.

Two examples of how engineers use their knowledge of atoms to create new technologies would be the following.

1.- Engineers can develop new medicines for chronic diseases when they use their knowledge about atoms. With new technologies and different scientific approaches, this new molecular medicine can be more effective in the treatment of terrible diseases that affect humans. The challenge lies in how to make these new medicines more affordable to all kinds of people, not only rich people.

2.- Engineers can also apply their knowledge about atoms to improve the water conditions so more people can have freshwater. Engineers that specialize in the environment can research the properties of water molecules and atoms, so they can develop new ways to purify and improve the quality of water, that we know that water scarcity is a major problem in many parts of the world.

4 0
4 years ago
PLSSS HELP ANYONE ASAP!
algol [13]
B I hope it’s right I don’t really help a lot but yeah lol
7 0
3 years ago
Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydr
xxTIMURxx [149]

Answer:

0.374 g

Explanation:

Hello,

Since both the molarity and the volume allows us to know the moles of potassium permanganate, and we already have the balanced chemical reaction, the stoichiometric procedure that is attached in the picture, is developed to substantiate the the titrated mass of hydrogen peroxide was 0.374 g.

Best regards.

6 0
4 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0
3 years ago
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