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2 years ago

Observe the reaction between N2 and H2 to make NH3.

Chemistry

1 answer:

GarryVolchara [31]2 years ago

6 0

Answer: , 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively

Explanation:

The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)

1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)

1) If 2 molecules of N2 react, then the balanced equation will be

2N2(g) + 6H2(g) → 4NH3(g)

Thus, 4 molecules of ammonia, NH3(g) is produced

2) If 3 molecules of H2 react, then the balanced equation will be

N2(g) + 3H2(g) → 2NH3(g)

Thus, 2 molecules of ammonia, NH3(g) is produced

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3 years ago

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(b) 118 g Cr₂O₃

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Step 1: Convert 156 g Cr₂S₃ to moles

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S Molar Mass - 32.07 g/mol × 3 = 96.21 g/mol

156 g Cr₂S₃ ÷ 200.21 g/mol = 0.779182 mol Cr₂S₃

Step 2: Find conversion from Cr₂S₃ to Cr₂O₃

1 mol Cr₂S₃ equals 1 mol Cr₂O₃

Step 3: Use Dimensional Analysis

0.779182 mol Cr₂S₃ · $\frac{1 \hspace{2} mol \hspace{2} Cr_2O_3}{1 \hspace{2} mol \hspace{2} Cr_2S_3}$ = 0.779182 mol Cr₂O₃

0.779182 mol Cr₂O₃ ≈ 0.779 mol Cr₂O₃ (3 significant figures)

Step 4: Convert moles to grams

Cr Molar Mass - 52.00 g/mol × 2 = 104.00 g/mol

O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol

0.779182 mol Cr₂O₃ · 152.00 g/mol = 118.436 g Cr₂O₃

118.436 g Cr₂O₃ ≈ 118 g Cr₂O₃ (3 significant figures)

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