Answer:
V₂ = 2.1 L
Explanation:
Given data:
Initial volume of balloon = 2.0 L
Initial temperature = 25°C
Final temperature = 35°C
Final volume of balloon in hot room = ?
Solution:
Initial temperature = 25°C (25+273= 298 K)
Final temperature = 35°C (35+273 = 308 k)
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 2.0 L × 308 K / 298 k
V₂ = 616 L.K / 298 K
V₂ = 2.1 L
Flammmability is a chemical change because it changes the composition of the object. the product is very different from the rectant.
The soda an air is most likely bubbling up and is going to explode.