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3 years ago

Number of neutrons for 9BE4

Chemistry

1 answer:

GREYUIT [131]3 years ago

8 0

Mass number - # of protons = #neutrons, so I would say the answer is 5

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What is the solute in the mixture of muddy water

yarga [219]

Answer:

A solute is a solid which dissolves in a solvent. Muddy water contains water and soil, soil does not dissolve in water

6 0

3 years ago

How many moles are in 2.1 x 10^{24} molecules SiO4

lozanna [386]

Answer: 3.5 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of SiO4 = 6.02 x 10^23 molecules

Zmoles of SiO4 = 2.1 x 10^{24} molecules

To get the value of Z, cross multiply:

(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)

Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)

Z = 3.5 moles

Thus, there are 3.5 moles of SiO4.

4 0

3 years ago

True or false???????????

Leni [432]

Answer:

false

Explanation:

longer the wave length less frequency

7 0

3 years ago

The combustion method used to analyze for carbon and hydrogen can be adapted to give percentage N by collecting the nitrogen fro

12345 [234]

Answer:

The percentage of N in the compound is 0.5088

Explanation:

Mass of compound = 8.75 mg = 8.75×1000 = 8750 g

Mass of N2 = number of moles of N2 × MW of N2 = 1.59 × 28 = 44.52 g

% of N in the compound = (mass of N2/mass of compound) × 100 = (44.52/8750) × 100 = 5.088×10^-3 × 100 = 0.5088

6 0

3 years ago

How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?

ankoles [38]

The chemical reaction equation for this is

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6,

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x $\frac{1 mole XeF6}{3 moles H2}$ x $\frac{245.28 g XeF6}{1 mole XeF6}$ = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.

3 0

4 years ago