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3 years ago

I need help with thissss

Mathematics

1 answer:

alexandr1967 [171]3 years ago

5 0

Answer:

#4 is option one 18 miles

Step-by-step explanation:

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Find the distance from the point (4,2) to the line y= −2.

riadik2000 [5.3K]

Answer:

The distance is 4.

Step-by-step explanation:

The shortest distance from the point (4,2) to the line y=-2, in this case, would be a straight line perpendicular to y=-2.

For each and every value of "x" on the line, y = -2. The shortest distance occurs at y(4) = - 2.

At this point the distance is:

$d^{2} =(4 - 4)^{2} + (2-(-2))^{2} \\d^{2} =4 ^{2}\\\\d = 4$

The distance is 4.

6 0

3 years ago

Divide fractions 1/2 divided by 1/6

SVEN [57.7K]

1/2 divided by 1/6 is 3

use KCF strategy

1/2 x 6/1=3

1x6=6

2x1=2

6/2=3

4 0

3 years ago

Find the peremiter of triangle ABC

cricket20 [7]

Answer:

Step-by-step explanation:

if AB : BC : AC is 3 : 4 : 2 and BC = 8 then AB = 6 and AC = 4

To calculate the perimeter of the triangle we add all side lengths up

4 + 6 + 8 = 18

5 0

2 years ago

Read 2 more answers

1. A-Tunes requires a membership fee of $12 a month and $1 for each download.

matrenka [14]

<h3>Answer:</h3>

After 16 downloads the charges will equal each other.

<h3>Step-by-step explanation:</h3>

First set up an equation

x = Downloads

12 + 1x = 5 + 1.5x

Solve

12 + 1x = 5 + 1.5x <- Rewrite your equation

-5 -5 <- Subtract 5 from both sides

8 + 1x = 1.5x <- Simplify

-1x -1x <- Subtract 1 from both sides

8 = 0.5x <- Simplify

8 = 1/2x <- Convert 0.5 to a fraction to make the next step easier

16 = x <- Multiply both sides by 2 to divide by

a fraction

4 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago