Answer:
The answer to your question is: 101.2 g of CO2
Explanation:
C = 27.6 g
O₂ = 86.5 g remained 12.9 g
O₂ that reacted = 86.5 - 12.9 = 73.6 g
C + O₂ ⇒ CO₂ The equation is balanced
27.6 73.6 ?
MW 12 32 44
Rule of three
12 g of C------------------ 44 g CO2
27.6 g C ------------------ x
x = 27.6(44)/12 = 101.2 g of CO2
32 g of O2 --------------- 44 g of CO2
73.6 g of O2 ------------ x
x = 73.6(44)/32 = 101.2 g of CO2
You can go to a website about that it will give you the answers
Answer:
The number of moles of O atom in 
mol of 
= 1.6
Explanation:
1 molecule of contains 2 atoms of O
So, 
molecules of contains 
atoms of O.
We know that 1 mol of an atom/molecule/ion represents 
numbers of atoms/molecules/ions respectively.
So, molecules of is equal to 1 mol of .
atoms of O is equal to 2 moles of O atom.
Hence, 1 mol of contains 2 moles of O atom.
Therefore, mol of contains 
moles of O atom or 1.6 moles of O atom.
Schrodinger developed a famous equation that allows the solutions for electron wave functions to be found given a specific potential. For the case of an atom, Schroginger's equation allows the determination of electron wave functions. These wave functions tell us how electrons are distributed in space around the atom.
