Answer:
1.99grams
Explanation:
- First, we need to calculate the molar mass of the compound: Ca(HCO3)2
Ca = 40g/mol, H = 1g/mol, C = 12g/mol, O = 16g/mol
Hence, Ca(HCO3)2
= 40 + {1 + 12 + 16(3)}2
= 40 + {13 + 48}2
= 40 + {61}2
= 40 + 122
= 162g/mol
Molar mass of Ca(HCO3)2 = 162g/mol
- Next, we calculate the mass of oxygen in one mole of the compound, Ca(HCO3)2.
Oxygen = {16(3)}2
= 48 × 2
= 96g of Oxygen
- Next, we calculate the percentage composition of oxygen by mass by dividing the mass of oxygen in the compound by the molar mass of the compound i.e.
% composition of O = 96/162 × 100
= 0.5926 × 100
= 59.26%.
- The number of moles of the compound, Ca(HCO3)2, must be converted to mass by using the formula; mole = mass/molar mass
0.0207 = mass/162
Mass = 162 × 0.0207
Mass = 3.353grams
However, in every gram of Ca(HCO3)2, there is 0.5926 g of oxygen
Hence, in 3.353grams of Ca(HCO3)2, there will be;
0.5926 × 3.353
= 1.986
= 1.99grams.
Therefore, there is 1.99grams of Oxygen in 0.0207 moles (3.353g) of Ca(HCO3)2.
Answer:
1 Mole O₂ / 2 Mole H₂O
Explanation:
The balance chemical equation for the synthesis of water is as follow,
2 H₂ + O₂ → 2 H₂O
In this equation the moles are specified by the coefficients i.e.
2 moles of H₂ reacting with 1 mole of O₂
2 moles of H₂ producing 2 moles of H₂O
1 mole of O₂ producing 2 moles of H₂O
Hence the molar ratio for O₂ and H₂O can be written as,
1 Mole O₂ : 2 Mole H₂O
or,
1 Mole O₂ / 2 Mole H₂O
Answer:
4.38 moles
Explanation:
It is the rounded off answer.
Answer: salt water is a mixture because it contains 2 substances.
Explanation:
Salt and water are both compounds when added together making it salt water it turns into a mixture
