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ElenaW [278]
3 years ago
9

Which is a true statement about the diagram? m∠5 + m∠6 = m∠1 m∠3 + m∠4 + m∠5 = 180° m∠1 + m∠2 = 180° m∠2 + m∠3 = m∠5

Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0

m<1 +m<2 = 180° is the answer

Elodia [21]3 years ago
7 0

Answer:

Third option is the right choice.

Step by step explanation:

We have been given an diagram and we are asked to choose the true statement about the diagram.

Let us see our all choices one by one.

1. m\angle5+m\angle6=m\angle1

We can see that \angle5 and \angle6 are supplementary and there measure should be equal to 180 degrees. \angle1 is exterior angle of our triangle and its measure must be equal to sum of measures of \angle5 and \angle3.

Therefore, 1st option is incorrect.  

2. m\angle3+m\angle4+m\angle5=180^{o}

We can see that \angle3 and \angle4 are supplementary and they must be equal to 180 degrees.  Therefore, 2nd option is also incorrect.

3. m\angle1+m\angle2=180^{o}

We can see from our diagram that \angle1 and \angle2 are supplementary. Therefore, 3rd option is the correct choice.

4. m\angle2+m\angle3=m\angle5

We can see that \angle2, \angle3 and \angle5 are interior angles of our triangle and their measure should be equal to 180 degrees. By exterior angle theorem sum of measures of \angle2 and \angle3 will be equal to measure of \angle6 instead of \angle5.

Therefore, our 4th option is also incorrect.

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STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

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SVETLANKA909090 [29]

Answer:

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Mariulka [41]

We know that m<JKL = m<JKM + m<MKL

Let's substitute the values from the picture into our equation above.

10x - 11 = 43 + 8x - 20

Combine like terms.

10x - 11 = 8x + 23

Subtract 8x from both sides and add 11 to both sides.

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m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.

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3 years ago
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