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ElenaW [278]
3 years ago
9

Which is a true statement about the diagram? m∠5 + m∠6 = m∠1 m∠3 + m∠4 + m∠5 = 180° m∠1 + m∠2 = 180° m∠2 + m∠3 = m∠5

Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0

m<1 +m<2 = 180° is the answer

Elodia [21]3 years ago
7 0

Answer:

Third option is the right choice.

Step by step explanation:

We have been given an diagram and we are asked to choose the true statement about the diagram.

Let us see our all choices one by one.

1. m\angle5+m\angle6=m\angle1

We can see that \angle5 and \angle6 are supplementary and there measure should be equal to 180 degrees. \angle1 is exterior angle of our triangle and its measure must be equal to sum of measures of \angle5 and \angle3.

Therefore, 1st option is incorrect.  

2. m\angle3+m\angle4+m\angle5=180^{o}

We can see that \angle3 and \angle4 are supplementary and they must be equal to 180 degrees.  Therefore, 2nd option is also incorrect.

3. m\angle1+m\angle2=180^{o}

We can see from our diagram that \angle1 and \angle2 are supplementary. Therefore, 3rd option is the correct choice.

4. m\angle2+m\angle3=m\angle5

We can see that \angle2, \angle3 and \angle5 are interior angles of our triangle and their measure should be equal to 180 degrees. By exterior angle theorem sum of measures of \angle2 and \angle3 will be equal to measure of \angle6 instead of \angle5.

Therefore, our 4th option is also incorrect.

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or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)

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Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp
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Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

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Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

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P(A ⋂ B) = 1 - P(A' ⋃ B')

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P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

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P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

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P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

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