Find the standard form of the equation of the parabola with a focus at (-4, 0) and a directrix at x = 4.
Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

Now we'll add 11 to both sides:

Which makes the left side a perfect square:

And now we can solve for x:

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:

Answer:
2 and 8, 3 and 5
Step-by-step explanation:
uh no explanation needed
Answer: 50 minutes
Step-by-step explanation: a quarter to 5 is always 15 minutes from 5, 4:45. So 5:35-4:45 is 50.