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velikii [3]
2 years ago
12

If x = 3 and y = 7 , evaluate the following expression: 20 − ( 3 y − 4 x )

Mathematics
2 answers:
xenn [34]2 years ago
6 0

Answer:

20-3(7)-4(3)

20-21-12

-13

Mariulka [41]2 years ago
4 0

Answer:

20 - (3(7) - 4(3)) = ?

20 - (21 - 12) = ?

20 - 9 = 11

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I need 4 numbers that equal 50 added together<br> no links
Svet_ta [14]

Answer:

1 + 49

2 + 48

3 + 47

4 + 46

5 + 45

6 + 44

7 + 43

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9 + 41

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8 0
3 years ago
An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0
zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

7 0
3 years ago
find the roots of the quadratic equation x^2-6x+k=0.giventhat one root is three times the other and that k is a constant.Also fi
arlik [135]

x_{1}  = 3x_{2}  \\ x_{1}  - 3x_{2}  = 0 ←relation \: 1\\ x_{1}  + x_{2}  = 6 ←relation \: 2

(x_{1},x_{2}) : (4.5,1.5)

k = x_{1}x_{2} = 4.5 \times 1.5 = 6.75

7 0
1 year ago
Question 10 of 12
kenny6666 [7]

Answer:

x = 11

Step-by-step explanation:

x + 8 = 19        subtract both sides by 8

x = 11

4 0
3 years ago
5 yards 2 feet × 2=​
klio [65]

Answer:

11 1/3 yards or 34 feet

6 0
4 years ago
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