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3 years ago

How does the increase of wavelength by 50% affect the frequency of a wave that travels in string?

Physics

1 answer:

kumpel [21]3 years ago

8 0

Answer:

Increasing the wavelength of a rope by 50 % decreases its frequency by 33 %. The new wavelength is 67 % of the original (33 % less than the original).

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Suppose that aliens from a planet orbiting Betelgeuse have eyes similar to human eyes, except that the diameter of their pupils

slega [8]

Answer:

Answered

Explanation:

The data given in the problem

Diameter of a human pupil=0.007 m=7 mm

Diameter of alien pupil=0.5=500 mm

Here we have to calculate the minimum distance at which the alien can see Betelgeuse i.e. the focal length (or the working distance). For this calculation we assume the eye to be a spherical lens.

The focal length and diameter of the lens are related by the formula $F=\frac{r}{2}$ Where r is radius of curvature i.e. d/2

Therefore for the alien, focal length= $F=\frac{25}{2}=12.5mm=0.0125F=\frac{25}{2}$ =12.5mm=0.0125

7 0

3 years ago

Tea in a kettle cools slowly but cools faster in cup<br><br>

skad [1K]

Explanation:

Tea cools faster in a cup than in a kettle because when it is on a cup it is more spread out so the cooler air around it is able to cool down each molecule faster than if it were in a kettle which is cooling down slower because the tea is not a spread out

7 0

3 years ago

Read 2 more answers

HELP ME DO THIS QUESTION PLEASE

raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0

3 years ago

Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f

Alex17521 [72]

Answer:

g' = g/4

Explanation:

The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
This force can be expressed according the Newton's Universal Law of Gravitation , as follows:

$F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} } (1)$

From Newton's 2nd Law, we have:
$F = m* a (2)$
Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

$g = G*\frac{m_{E} }{r_{E}^{2} } (3)$

Since G is an universal constant, and the mass mE remains constant, if we double the radius of the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

$g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} } = g*\frac{1}{4} =\frac{g}{4} (4)$

4 0

3 years ago

Please help quick please its a test

navik [9.2K]

Answer:

Im pretty sure its y!

Explanation:

6 0

3 years ago