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4 years ago

12

A tuning fork vibrates 240 times per second. What is the frequency and period?

1 answer:

Grace [21]4 years ago

8 0

Answer:

Frequency is expressed in Hertz, which is simply cycles per second. If a tuning fork (or anything else, for that matter) vibrates 1 time each second, it's frequency is 1 Hz. So then, if it vibrates 4280 in 20 seconds, then 4280÷20=214 cycles per second = 214 Hz.

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A dog runs down his driveway with an initial speed of 5 m/s for 8 s, and then uniformly increases his speed to 10 m/s in 5 s.

MakcuM [25]

Acceleration is given by change in velocity divided by change in time, so his acceleration should just be (10-5)/5 which is [tex] \frac{5}{2} \frac{m}{s^{2}} [tex]

The driveway is 40 meters plus 225/4. You can do the math.

8 0

4 years ago

(a) What is the acceleration due to gravity on the surface of the Moon?

wolverine [178]

<h2>a) Acceleration due to gravity on the surface of the Moon is 1.64 m/s²</h2><h2>b) Acceleration due to gravity on the surface of the Mars is 3.75 m/s²</h2>

Explanation:

a) Acceleration due to gravity

$g=\frac{GM}{r^2}$

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

Mass of moon, M = 7.35 × 10²² kg

Radius of moon, r = 1.73 × 10⁶ m

Substituting

$g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.73\times 10^{6})^2}=1.64m/s^2$

Acceleration due to gravity on the surface of the Moon is 1.64 m/s²

b) Acceleration due to gravity

$g=\frac{GM}{r^2}$

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

Mass of Mars, M = 6.418 × 10²³ kg

Radius of Mars, r = 3.38 × 10⁶ m

Substituting

$g=\frac{6.67\times 10^{-11}\times 6.418\times 10^{23}}{(3.38\times 10^{6})^2}=3.75m/s^2$

Acceleration due to gravity on the surface of the Mars is 3.75 m/s²

7 0

3 years ago

What is the answer ?

Fofino [41]

P= mv
p=(.5)(20)
p=10 kg/ms

7 0

3 years ago

Diffraction of sound waves is demonstrated when sound waves with a frequency of 1300 Hz from a distant source are diffracted thr

Tresset [83]

Answer:

39.05°

Explanation:

As we know that, the diffraction is the phenomena of bending of light when it passes through an obstacle.

Mathematically,

$dsin\theta=n\lambda$

Here, d is slit width, $\lambda$ is the wavelength, n is the order, $\theta$ is the angle.

Given that, d is 84 cm, n is 2, and the wavelength can be calculated as,

$\lambda=\frac{c}{f}$

Here, c is the speed of sound and f is the frequency of sound wave.

Here, c is 343 m/s and f is 1300 Hz,

Therefore,

$\lambda=\frac{343 m/s}{1300 Hz}\\\lambda=0.264m$

Recall diffraction equation in term of $sin\theta$ .

$sin\theta=\frac{n\lambda}{d}$

Put all the variables.

$sin\theta=\frac{2\times 0.264 m}{84 cm}\\sin\theta=\frac{2\times 0.264 m}{0.84 m}\\\theta=39.05^{\circ}$

Therefore, it is the required angle between the first 2 order of diffraction.

3 0

3 years ago

How would life on earth be different if its axis was not tilted with respect to its orbit?.

borishaifa [10]

Answer:

oone side at a time would be hot and the other oone

Explanation:

One side will be hot and the other cold no in-between

3 0

2 years ago