1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arlecino [84]
4 years ago
6

Waxed paper and frosted glass are examples of materials that are transparent.

Physics
2 answers:
GREYUIT [131]4 years ago
8 0
Waxed paper and frosted glass are NOT examples of transparent materials they are however translucent materials. A transparent material is something that you can see through so an example would be water.
inysia [295]4 years ago
5 0
They are translucent materials, so false.
You might be interested in
Help it’s multiple choice 11 through 15 please!
riadik2000 [5.3K]

1. • Here, force of gravity on the block = 20 N.

• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]

• The coefficient

u_{k} = 0.4

• Force of friction =

u_{k} \times  \: normal \:  \:  \: force \\  = 0.4 \times 20N \\  = 8N

• Hence, the force of sliding friction between the block and the ground is 8 N.

• So, it is option c. 8 N

2. The answer is option d. continue in the same direction with no change in speed.

We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.

3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.

Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.

So, 1 N = 1 Kg × 1 m/s^2.

4. It is d. not zero.

Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.

5. Force = 2 N

Acceleration of the object A = 2 m/s^2.

Acceleration of the object B = 1 m/s^2.

Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg

And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg

So, the mass of object B is greater than that of object A.

Hence, the answer is option c. Object B has more mass.

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0
2 years ago
Does anyone know the answer to all of these questions
Rasek [7]

Answer:

i don't understand the hw

5 0
3 years ago
The movement of air around an anticyclone is:
N76 [4]
Pretty sure it is clockwise if I am not mistaken
5 0
3 years ago
Read 2 more answers
Why does the frequency of a siren get higher as an ambulance using that siren gets closer​
morpeh [17]
Yes it does that’s correct
6 0
3 years ago
An electrician timed a box traveling over a conveyor and measured 25 sec to travel 30 feet. If the gearbox ratio is 20:1 and the
nataly862011 [7]
Pppeejsidoocicjddkdkcocfoodoocoie
4 0
4 years ago
Other questions:
  • A bullet with a mass ????b=13.5mb=13.5 g is fired into a block of wood at velocity ????b=253vb=253 m/s. The block is attached to
    7·1 answer
  • I need help fast!!!
    6·1 answer
  • 60mil/hr to m/s convert
    14·1 answer
  • What is the term for movement in a particular direction
    13·1 answer
  • Lucas plugs a lamp into the wall. The light bulb in the lamp turns on. What kind of energy transformation is this? A.)Light ener
    9·2 answers
  • The blade of a metal cutter is shorter than that of the scissors used by tailor.why​
    8·1 answer
  • When a pendulum is at the position all the way to the left when it is swinging (at the top of the arc), what is true of the kine
    14·2 answers
  • Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it trie
    9·1 answer
  • At which latitude would tropical rain forests be most likely?
    15·1 answer
  • Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!