Help please!!!!!!!!!!!!!!!!!!!
1 answer:
You might be interested in
Answer: 19.93 minutes
Explanation:
This is the complete question
Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil and lube service at this garage is 15 minutes per car and the standard deviation is 2.4 minutes. The management wants to promote the business by guaranteeing a maximum waiting time for its customers. If a customer's car is not serviced within that period, the customer will receive a 50% discount on the charges. The company wants to limit this discount to at most 2% of the customers. What should the maximum guaranteed waiting time be? Assume that the times taken for oil and lube service for all cars have a normal distribution
The solution is attached below
Answer:
$224,174
Explanation:
Note : I have uploaded the full question below :
The Principle P that is required can be calculated from the given data though discounting future cash flows as follows :
FV = $1,000,000
r = 7½%
t = 20 × 12 = 240
P/yr = 12
Pmt = $0
PV = ?
Using a Financial Calculator to input the values as shown above, the PV would be $224,174 . Thus, the principal P that must be invested must be $224,174.
